More about Coordinate Systems
Contents
More about Coordinate Systems¶
We will now look at how we can initialize new coordinate systems in
sympy.vector
, transformed in user-defined
ways with respect to already-existing systems.
Locating new systems¶
We already know that the origin
property of a
CoordSys3D
corresponds to the Point
instance
denoting its origin reference point.
Consider a coordinate system \(N\). Suppose we want to define a new system \(M\), whose origin is located at \(\mathbf{3\hat{i} + 4\hat{j} + 5\hat{k}}\) from \(N\)’s origin. In other words, the coordinates of \(M\)’s origin from N’s perspective happen to be \((3, 4, 5)\). Moreover, this would also mean that the coordinates of \(N\)’s origin with respect to \(M\) would be \((-3, -4, -5)\).
This can be achieved programmatically as follows -
>>> from sympy.vector import CoordSys3D
>>> N = CoordSys3D('N')
>>> M = N.locate_new('M', 3*N.i + 4*N.j + 5*N.k)
>>> M.position_wrt(N)
3*N.i + 4*N.j + 5*N.k
>>> N.origin.express_coordinates(M)
(-3, -4, -5)
It is worth noting that \(M\)’s orientation is the same as that of
\(N\). This means that the rotation matrix of :math: \(N\) with respect
to \(M\), and also vice versa, is equal to the identity matrix of
dimensions 3x3.
The locate_new
method initializes a CoordSys3D
that
is only translated in space, not re-oriented, relative to the ‘parent’
system.
Orienting new systems¶
Similar to ‘locating’ new systems, sympy.vector
also allows for
initialization of new CoordSys3D
instances that are oriented
in user-defined ways with respect to existing systems.
Suppose you have a coordinate system \(A\).
>>> from sympy.vector import CoordSys3D
>>> A = CoordSys3D('A')
You want to initialize a new coordinate system \(B\), that is rotated with respect to \(A\)’s Z-axis by an angle \(\theta\).
>>> from sympy import Symbol
>>> theta = Symbol('theta')
The orientation is shown in the diagram below:
There are two ways to achieve this.
Using a method of CoordSys3D directly¶
This is the easiest, cleanest, and hence the recommended way of doing it.
>>> B = A.orient_new_axis('B', theta, A.k)
This initializes \(B\) with the required orientation information with respect to \(A\).
CoordSys3D
provides the following direct orientation methods
in its API-
orient_new_axis
orient_new_body
orient_new_space
orient_new_quaternion
Please look at the CoordSys3D
class API given in the docs
of this module, to know their functionality and required arguments
in detail.
Using Orienter(s) and the orient_new method¶
You would first have to initialize an AxisOrienter
instance for
storing the rotation information.
>>> from sympy.vector import AxisOrienter
>>> axis_orienter = AxisOrienter(theta, A.k)
And then apply it using the orient_new
method, to obtain \(B\).
>>> B = A.orient_new('B', axis_orienter)
orient_new
also lets you orient new systems using multiple
Orienter
instances, provided in an iterable. The rotations/orientations
are applied to the new system in the order the Orienter
instances
appear in the iterable.
>>> from sympy.vector import BodyOrienter
>>> from sympy.abc import a, b, c
>>> body_orienter = BodyOrienter(a, b, c, 'XYZ')
>>> C = A.orient_new('C', (axis_orienter, body_orienter))
The sympy.vector
API provides the following four Orienter
classes for orientation purposes-
AxisOrienter
BodyOrienter
SpaceOrienter
QuaternionOrienter
Please refer to the API of the respective classes in the docs of this module to know more.
In each of the above examples, the origin of the new coordinate system coincides with the origin of the ‘parent’ system.
>>> B.position_wrt(A)
0
To compute the rotation matrix of any coordinate system with respect
to another one, use the rotation_matrix
method.
>>> B = A.orient_new_axis('B', a, A.k)
>>> B.rotation_matrix(A)
Matrix([
[ cos(a), sin(a), 0],
[-sin(a), cos(a), 0],
[ 0, 0, 1]])
>>> B.rotation_matrix(B)
Matrix([
[1, 0, 0],
[0, 1, 0],
[0, 0, 1]])
Orienting AND Locating new systems¶
What if you want to initialize a new system that is not only oriented in a pre-defined way, but also translated with respect to the parent?
Each of the orient_new_<method of orientation>
methods, as well
as the orient_new
method, support a location
keyword
argument.
If a Vector
is supplied as the value for this kwarg
, the
new system’s origin is automatically defined to be located at that
position vector with respect to the parent coordinate system.
Thus, the orientation methods also act as methods to support orientation+ location of the new systems.
>>> C = A.orient_new_axis('C', a, A.k, location=2*A.j)
>>> C.position_wrt(A)
2*A.j
>>> from sympy.vector import express
>>> express(A.position_wrt(C), C)
(-2*sin(a))*C.i + (-2*cos(a))*C.j
More on the express
function in a bit.
Transforming new system¶
The most general way of creating user-defined system is to use
transformation
parameter in CoordSys3D
. Here we can define
any transformation equations. If we are interested in some typical
curvilinear coordinate system different that Cartesian, we can also
use some predefined ones. It could be also possible to translate or
rotate system by setting appropriate transformation equations.
>>> from sympy.vector import CoordSys3D
>>> from sympy import sin, cos
>>> A = CoordSys3D('A', transformation='spherical')
>>> B = CoordSys3D('A', transformation=lambda x,y,z: (x*sin(y), x*cos(y), z))
In CoordSys3D
is also dedicated method, create_new
which works
similarly to methods like locate_new
, orient_new_axis
etc.
>>> from sympy.vector import CoordSys3D
>>> A = CoordSys3D('A')
>>> B = A.create_new('B', transformation='spherical')
Expression of quantities in different coordinate systems¶
Vectors and Dyadics¶
As mentioned earlier, the same vector attains different expressions in different coordinate systems. In general, the same is true for scalar expressions and dyadic tensors.
sympy.vector
supports the expression of vector/scalar quantities
in different coordinate systems using the express
function.
For purposes of this section, assume the following initializations-
>>> from sympy.vector import CoordSys3D, express
>>> from sympy.abc import a, b, c
>>> N = CoordSys3D('N')
>>> M = N.orient_new_axis('M', a, N.k)
Vector
instances can be expressed in user defined systems using
express
.
>>> v1 = N.i + N.j + N.k
>>> express(v1, M)
(sin(a) + cos(a))*M.i + (-sin(a) + cos(a))*M.j + M.k
>>> v2 = N.i + M.j
>>> express(v2, N)
(1 - sin(a))*N.i + (cos(a))*N.j
Apart from Vector
instances, express
also supports
reexpression of scalars (general SymPy Expr
) and
Dyadic
objects.
express
also accepts a second coordinate system
for re-expressing Dyadic
instances.
>>> d = 2*(M.i | N.j) + 3* (M.j | N.k)
>>> express(d, M)
(2*sin(a))*(M.i|M.i) + (2*cos(a))*(M.i|M.j) + 3*(M.j|M.k)
>>> express(d, M, N)
2*(M.i|N.j) + 3*(M.j|N.k)
Coordinate Variables¶
The location of a coordinate system’s origin does not affect the
re-expression of BaseVector
instances. However, it does affect
the way BaseScalar
instances are expressed in different systems.
BaseScalar
instances, are coordinate ‘symbols’ meant to denote the
variables used in the definition of vector/scalar fields in
sympy.vector
.
For example, consider the scalar field \(\mathbf{{T}_{N}(x, y, z) = x + y + z}\) defined in system \(N\). Thus, at a point with coordinates \((a, b, c)\), the value of the field would be \(a + b + c\). Now consider system \(R\), whose origin is located at \((1, 2, 3)\) with respect to \(N\) (no change of orientation). A point with coordinates \((a, b, c)\) in \(R\) has coordinates \((a + 1, b + 2, c + 3)\) in \(N\). Therefore, the expression for \(\mathbf{{T}_{N}}\) in \(R\) becomes \(\mathbf{{T}_{R}}(x, y, z) = x + y + z + 6\).
Coordinate variables, if present in a vector/scalar/dyadic expression,
can also be re-expressed in a given coordinate system, by setting the
variables
keyword argument of express
to True
.
The above mentioned example, done programmatically, would look like this -
>>> R = N.locate_new('R', N.i + 2*N.j + 3*N.k)
>>> T_N = N.x + N.y + N.z
>>> express(T_N, R, variables=True)
R.x + R.y + R.z + 6
Other expression-dependent methods¶
The to_matrix
method of Vector
and
express_coordinates
method of Point
also return
different results depending on the coordinate system being provided.
>>> P = R.origin.locate_new('P', a*R.i + b*R.j + c*R.k)
>>> P.express_coordinates(N)
(a + 1, b + 2, c + 3)
>>> P.express_coordinates(R)
(a, b, c)
>>> v = N.i + N.j + N.k
>>> v.to_matrix(M)
Matrix([
[ sin(a) + cos(a)],
[-sin(a) + cos(a)],
[ 1]])
>>> v.to_matrix(N)
Matrix([
[1],
[1],
[1]])